Subtract a time interval from a date. This function calculates a past date by subtracting a specified unit, such as days, from a starting value.
DATE_SUB(date,INTERVAL expr unit)Performs date arithmetic. The date argument specifies the starting date or datetime value. expr is an expression specifying the interval value to be subtracted from the starting date. expr is a string; it may start with a "-" for negative intervals. unit is a keyword indicating the units in which the expression should be interpreted. See for a complete list of permitted units.
See also .
This page is licensed: GPLv2, originally from
SELECT DATE_SUB('1998-01-02', INTERVAL 31 DAY);
+-----------------------------------------+
| DATE_SUB('1998-01-02', INTERVAL 31 DAY) |
+-----------------------------------------+
| 1997-12-02 |
+-----------------------------------------+SELECT DATE_SUB('2005-01-01 00:00:00', INTERVAL '1 1:1:1' DAY_SECOND);
+----------------------------------------------------------------+
| DATE_SUB('2005-01-01 00:00:00', INTERVAL '1 1:1:1' DAY_SECOND) |
+----------------------------------------------------------------+
| 2004-12-30 22:58:59 |
+----------------------------------------------------------------+