Comments - How to escape backslash in an insert statement

10 years ago Manju Raphel

Thanks. I did some more testing with the seconds variant. It works fine when I use regular JDBC. It was giving the error when ran the update via Spring JDBC Template.

I was using it like below: jdbcTemplate.update(stmt, new Object[0]); This uses prepared statement internally

It works fine if I don't pass the empty argument list. jdbcTemplate.update(stmt); works

Not sure why it is different. Anyway, I can use the option without the argument list.

Thanks! Manju

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