Comments - How to escape backslash in an insert statement
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Thanks. I did some more testing with the seconds variant. It works fine when I use regular JDBC. It was giving the error when ran the update via Spring JDBC Template.
I was using it like below: jdbcTemplate.update(stmt, new Object); This uses prepared statement internally
It works fine if I don't pass the empty argument list. jdbcTemplate.update(stmt); works
Not sure why it is different. Anyway, I can use the option without the argument list.