The Ultimate Guide to High Availability with MariaDB

Comments - JSON_INSERT

2 years, 6 months ago rank rao
Re: JSON_INSERT

can i insert wiith a josn,not a string? just like this

it use as a string

mysql> SET @j = '{ "a": 1, "b": [2, 3]}';
mysql> SELECT JSON_INSERT(@j, '$.a', 10, '$.c', '[true, false]');
+----------------------------------------------------+
| JSON_INSERT(@j, '$.a', 10, '$.c', '[true, false]') |
+----------------------------------------------------+
| {"a": 1, "b": [2, 3], "c": "[true, false]"}        |
+----------------------------------------------------+

it use as a json

mysql> SELECT JSON_INSERT(@j, '$.a', 10, '$.c', CAST('[true, false]' AS JSON));
+------------------------------------------------------------------+
| JSON_INSERT(@j, '$.a', 10, '$.c', CAST('[true, false]' AS JSON)) |
+------------------------------------------------------------------+
| {"a": 1, "b": [2, 3], "c": [true, false]}                        |
+------------------------------------------------------------------+
1 row in set (0.00 sec)
 
2 years, 6 months ago Markus Mäkelä
Re: JSON_INSERT

You can use JSON_EXTRACT for it:

MariaDB [test]> SET @j = '{ "a": 1, "b": [2, 3]}';
Query OK, 0 rows affected (0.000 sec)

MariaDB [test]> SELECT JSON_INSERT(@j, '$.a', 10, '$.c', JSON_EXTRACT('[true, false]', '$'));
+-----------------------------------------------------------------------+
| JSON_INSERT(@j, '$.a', 10, '$.c', JSON_EXTRACT('[true, false]', '$')) |
+-----------------------------------------------------------------------+
| {"a": 1, "b": [2, 3], "c": [true, false]}                             |
+-----------------------------------------------------------------------+
1 row in set (0.000 sec)
 
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