Pivoting in MariaDB
The problem
A solution
Reference code for solution
DELIMITER //
DROP PROCEDURE IF EXISTS Pivot //
CREATE PROCEDURE Pivot(
IN tbl_name VARCHAR(99), -- table name (or db.tbl)
IN base_cols VARCHAR(99), -- column(s) on the left, separated by commas
IN pivot_col VARCHAR(64), -- name of column to put across the top
IN tally_col VARCHAR(64), -- name of column to SUM up
IN where_clause VARCHAR(99), -- empty string or "WHERE ..."
IN order_by VARCHAR(99) -- empty string or "ORDER BY ..."; usually the base_cols
)
DETERMINISTIC
SQL SECURITY INVOKER
BEGIN
-- Find the distinct values
-- Build the SUM()s
SET @subq = CONCAT('SELECT DISTINCT ', pivot_col, ' AS val ',
' FROM ', tbl_name, ' ', where_clause, ' ORDER BY 1');
-- select @subq;
SET @cc1 = "CONCAT('SUM(IF(&p = ', &v, ', &t, 0)) AS ', &v)";
SET @cc2 = REPLACE(@cc1, '&p', pivot_col);
SET @cc3 = REPLACE(@cc2, '&t', tally_col);
-- select @cc2, @cc3;
SET @qval = CONCAT("'\"', val, '\"'");
-- select @qval;
SET @cc4 = REPLACE(@cc3, '&v', @qval);
-- select @cc4;
SET SESSION group_concat_max_len = 10000; -- just in case
SET @stmt = CONCAT(
'SELECT GROUP_CONCAT(', @cc4, ' SEPARATOR ",\n") INTO @sums',
' FROM ( ', @subq, ' ) AS top');
select @stmt;
PREPARE _sql FROM @stmt;
EXECUTE _sql; -- Intermediate step: build SQL for columns
DEALLOCATE PREPARE _sql;
-- Construct the query and perform it
SET @stmt2 = CONCAT(
'SELECT ',
base_cols, ',\n',
@sums,
',\n SUM(', tally_col, ') AS Total'
'\n FROM ', tbl_name, ' ',
where_clause,
' GROUP BY ', base_cols,
'\n WITH ROLLUP',
'\n', order_by
);
select @stmt2; -- The statement that generates the result
PREPARE _sql FROM @stmt2;
EXECUTE _sql; -- The resulting pivot table ouput
DEALLOCATE PREPARE _sql;
-- For debugging / tweaking, SELECT the various @variables after CALLing.
END;
//
DELIMITER ;Variants
Postlog
See Also
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