LAG
Access data from a preceding row. This function returns the value of an expression from a row at a specified physical offset prior to the current row.
Syntax
LAG (expr[, offset]) OVER (
[ PARTITION BY partition_expression ]
< ORDER BY order_list >
)Description
Examples
CREATE TABLE t1 (pk int primary key, a int, b int, c char(10), d decimal(10, 3), e real);
INSERT INTO t1 VALUES
( 1, 0, 1, 'one', 0.1, 0.001),
( 2, 0, 2, 'two', 0.2, 0.002),
( 3, 0, 3, 'three', 0.3, 0.003),
( 4, 1, 2, 'three', 0.4, 0.004),
( 5, 1, 1, 'two', 0.5, 0.005),
( 6, 1, 1, 'one', 0.6, 0.006),
( 7, 2, NULL, 'n_one', 0.5, 0.007),
( 8, 2, 1, 'n_two', NULL, 0.008),
( 9, 2, 2, NULL, 0.7, 0.009),
(10, 2, 0, 'n_four', 0.8, 0.010),
(11, 2, 10, NULL, 0.9, NULL);
SELECT pk, LAG(pk) OVER (ORDER BY pk) AS l,
LAG(pk,1) OVER (ORDER BY pk) AS l1,
LAG(pk,2) OVER (ORDER BY pk) AS l2,
LAG(pk,0) OVER (ORDER BY pk) AS l0,
LAG(pk,-1) OVER (ORDER BY pk) AS lm1,
LAG(pk,-2) OVER (ORDER BY pk) AS lm2
FROM t1;
+----+------+------+------+------+------+------+
| pk | l | l1 | l2 | l0 | lm1 | lm2 |
+----+------+------+------+------+------+------+
| 1 | NULL | NULL | NULL | 1 | 2 | 3 |
| 2 | 1 | 1 | NULL | 2 | 3 | 4 |
| 3 | 2 | 2 | 1 | 3 | 4 | 5 |
| 4 | 3 | 3 | 2 | 4 | 5 | 6 |
| 5 | 4 | 4 | 3 | 5 | 6 | 7 |
| 6 | 5 | 5 | 4 | 6 | 7 | 8 |
| 7 | 6 | 6 | 5 | 7 | 8 | 9 |
| 8 | 7 | 7 | 6 | 8 | 9 | 10 |
| 9 | 8 | 8 | 7 | 9 | 10 | 11 |
| 10 | 9 | 9 | 8 | 10 | 11 | NULL |
| 11 | 10 | 10 | 9 | 11 | NULL | NULL |
+----+------+------+------+------+------+------+See Also
Last updated
Was this helpful?

